(x)=2x^2-16x+5

Solution for (x)=2x^2-16x+5 equation:

(x)=2x^2-16x+5

We move all terms to the left:

(x)-(2x^2-16x+5)=0

We get rid of parentheses

-2x^2+x+16x-5=0

We add all the numbers together, and all the variables

-2x^2+17x-5=0

a = -2; b = 17; c = -5;
Δ = b2-4ac
Δ = 172-4·(-2)·(-5)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{249}}{2*-2}=\frac{-17-\sqrt{249}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{249}}{2*-2}=\frac{-17+\sqrt{249}}{-4}
$